2[3r+4]-3[r+1]=11

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Solution for 2[3r+4]-3[r+1]=11 equation:


Simplifying
2[3r + 4] + -3[r + 1] = 11

Reorder the terms:
2[4 + 3r] + -3[r + 1] = 11
[4 * 2 + 3r * 2] + -3[r + 1] = 11
[8 + 6r] + -3[r + 1] = 11

Reorder the terms:
8 + 6r + -3[1 + r] = 11
8 + 6r + [1 * -3 + r * -3] = 11
8 + 6r + [-3 + -3r] = 11

Reorder the terms:
8 + -3 + 6r + -3r = 11

Combine like terms: 8 + -3 = 5
5 + 6r + -3r = 11

Combine like terms: 6r + -3r = 3r
5 + 3r = 11

Solving
5 + 3r = 11

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 3r = 11 + -5

Combine like terms: 5 + -5 = 0
0 + 3r = 11 + -5
3r = 11 + -5

Combine like terms: 11 + -5 = 6
3r = 6

Divide each side by '3'.
r = 2

Simplifying
r = 2

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